Mendelian Principles - Independent Assortment
Mendel looked at crosses involving pea plants that differed in two characters. From his initial experiments, he had already demonstrated that each trait showed segregation.
Pod color Green > Yellow [ A > a ]
Pod Form Inflated > Constricted [ B > b ]
P1 Inflated green x Constricted Yellow
F1 All inflated green
F2 Inflated Green 9
Inflated yellow3
Constricted Green 3
Constricted yellow 1
Ways of calculating F2 results
Punnett Square
AB Ab aB ab
============================================
AB AABB AABb AaBB AaBb
Ab AABb AAbb AaBb Aabb
aB AaBB AaBb aaBB aaBb
ab AaBb Aabb aaBb aabb
Count up appropriate genotypes to get the appropriate phenotypes.
A_B_ = 1 AABB: 2 AABb: 4 AaBb: 2 AaBB = 9
A_bb = 1 AAbb: 2 Aabb = 3
aaB_ = 1 aaBB: 2 aaBb = 3
aabb = 1 aabb = 1
A second way is to use segregation at each locus
Segregation at A locus: 3 green to 1 yellow
Segregation at B locus: 3 inflated to 1 constricted
Multiple the binomial together
[3(green): 1(yellow)] x [ 3(inflated): 1 (constr)]
9(infl, green): 3(infl, yel.): 3(const., green): 1(const, yel).
Independent assortment:
It says that every trait is inherited independently of the others and it thus covers the case that new combinations of genes can arise, which were not existing before. We know today that this principle is just valid in the case of genes that are not coupled, i.e. that are not located at the same chromosome.
Alleles at one locus loci segregate into gametes independently of alleles at other loci. Such gametes are formed in equal frequencies: Subsequent fertilization is at random.
Example:
1 locus Aa = 2 gametes a & A with freq. of 1/2
2 loci AaBb = 4 gametes AB, Ab, aB, & ab with freq. of 1/4
3 loci AaBbCc = 8 gametes ABC, ABc, AbC, Abc, aBC, aBc, abC, & abc each with freq. 1/8
The expected distributions are combinatorial series for each character. That is for two characters A and B the disftibution of genotypes would be (A + 2Aa+ a) (B + 2Bb + b)
Note: Mendel also developed trihybrid crosses.
Test Cross - 2 loci
A_B_ might be one of four genotypes with following results
Phenotypes
AB Ab aB ab Genotype
==========================================
AABBx aabb 1 AABB
AaBB x aabb 1 1 AaBB
AABb x aabb 1 1 AABb
AaBb x aabb 1 1 1 1 AaBb